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I-V characteristics required practical

In the I-V characteristics required practical, you change the potential difference across a component, measure the current through it each time, and plot current against potential difference. You do it for three components: a filament lamp, a resistor and a diode. It is required practical 4 in AQA's GCSE Physics and required practical 16 in Combined Science Trilogy. This guide covers the practical itself; our guide to I-V characteristics explains why each graph has its shape.

Aim

AQA's specification states the aim as: use circuit diagrams to construct appropriate circuits to investigate the I-V characteristics of a variety of circuit elements, including a filament lamp, a diode and a resistor at constant temperature.

Equipment

AQA's student sheet lists:

  • a digital ammeter and a digital voltmeter;
  • a milliammeter, for the diode;
  • a variable resistor, a battery or power supply, and connecting leads;
  • a filament lamp, a resistor and a diode;
  • an extra resistor labelled P, to protect the diode.

The teacher notes suggest a 12 V, 24 W filament lamp, such as a ray box lamp. With a variable power supply you can change the potential difference directly and leave out the variable resistor.

AVpower supplyvariable resistorlamp
The ammeter goes in series with the component and the voltmeter in parallel across it

Method

These steps follow AQA's student sheet, which runs the three parts in one lesson, in this order.

Activity 1: filament lamp

  1. Set up the circuit in the diagram.
  2. Record the ammeter and voltmeter readings in a table.
  3. Adjust the variable resistor and record the new readings. Repeat to get several pairs of readings.
  4. Swap the connections on the power supply. The readings should now be negative.
  5. Record several more pairs of readings with the supply reversed.
  6. Plot current against potential difference. With negative values, the origin goes in the middle of the graph paper.

Activity 2: resistor

Swap the supply leads back, replace the lamp with the resistor, and repeat steps 2 to 6. This time you should get a straight line passing through the origin.

Activity 3: diode

Swap the supply leads back. If you can, reduce the supply to less than 5 V. Connect resistor P in series, replace the ammeter with the milliammeter, and replace the resistor with the diode. Then repeat steps 2 to 6. The voltmeter still goes across the diode alone.

Variables

TypeVariable
IndependentPotential difference across the component
DependentCurrent through the component
ControlThe component, and for the resistor its temperature

Results table

Use one table for each component, with positive and negative readings:

Potential difference (V)Current (A)Resistance (Ω)
−4.0|
−2.0|
0.0|
2.0|
4.0|

For the diode, record the current in mA, from the milliammeter.

How to analyse the results

Plot current on the y-axis against potential difference on the x-axis, then work out the resistance at each reading with:

R = \frac{V}{I}

AQA's handbook warns that many students think the gradient of the graph is the resistance. It isn't: the resistance at any point is 1 ÷ the gradient of a straight line from that point to the origin, which is the same as V ÷ I.

Example results for a filament lamp

Modelled readings for a 12 V, 24 W lamp, to show the shape: for illustration, not measured. Your own results will differ.

Potential difference (V)Current (A)Resistance, V ÷ I (Ω)
2.00.752.7
4.01.093.7
8.01.605.0
12.02.006.0

The resistance rises as the filament gets hotter. At its rated 12 V, the lamp takes 24 ÷ 12 = 2.0 A, so its resistance is 6.0 Ω.

For the resistor, current is directly proportional to potential difference, so the gradient of its line is 1 ÷ R. The Practical Data Lab finds the gradient of your best-fit line, with its uncertainty, from your readings.

practice
Pick an answer, then check it.
A resistor's I-V line passes through the origin and the point (6.0 V, 0.12 A). What is its resistance?

Now try one in the course. Read the resistance from the graph, then press Mark to check it there.

Read a resistor's I-V graph to find its resistance or a current.

Press Mark to have your answer marked in the Electricity course.

Risks

HazardRiskPrecaution
Filament lamp gets hotBurnsDo not touch it while lit; let it cool before changing it
Resistor heats up with large currentsBurns, and its resistance changesKeep currents small; switch off between readings
Too large a potential differenceDamaged componentsCheck their ratings; always use resistor P with the diode

Errors and improvements

  • The resistor warms up. The aim says constant temperature, so keep the current small and switch off between readings.
  • Too few readings where the graph bends. Take more readings where the lamp curve flattens and where the diode's current starts to rise.
  • Diode currents too small to read. Use the milliammeter, as AQA's sheet does.

Common mistakes

  • Putting the voltmeter in series. It goes in parallel across the component; the ammeter goes in series.
  • Taking the gradient as the resistance. Use R = V ÷ I at the point.
  • Plotting only positive values. Reverse the supply to show the full characteristic, especially for the diode.
  • Axes the wrong way round. AQA plots current on the y-axis and potential difference on the x-axis.

I-V practical questions with answers

1. Why is the ammeter connected in series with the component?
So the same current flows through the ammeter and the component.
2. Why are the supply connections swapped part way through?
To get negative values of potential difference and current, so the whole characteristic is plotted.
3. A filament lamp takes 0.25 A at 6.0 V. Find its resistance.
R = 6.0 ÷ 0.25 = 24 Ω
4. Why is a milliammeter used for the diode?
The diode's currents are very small, too small to read accurately on an ammeter.
5. Why do you switch off between readings for the resistor?
So it does not heat up, because a change in temperature would change its resistance.

The Circuit Builder has a ready-made Lamp I-V experiment with this circuit. Drag the variable resistor and select the lamp to see its I-V curve. It has LEDs but no ordinary diodes.

Try it

Circuit Builder

Build any DC circuit with meters, lamps, LEDs and sensors, and see live readings

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Practise physics in a short timed paper

GCSE Physics Higher gives you a short timed paper every day, with 8 questions worth 25 to 35 marks across the course, so electricity and required practicals turn up regularly but not in every paper.

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Common questions

What is the I-V characteristics required practical?
An investigation of how the current through a filament lamp, a resistor and a diode changes as the potential difference across each one changes.
Why does the diode need a protective resistor?
To stop the current through it getting large enough to damage it.

Revision cards

Say the answer first, then flip the card to check it.

Where to go next

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