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PhysicsFields and gravity

Coulomb's law

Coulomb's law gives the force between two point charges: F = Q₁Q₂ ÷ (4πε₀r²), often written F = kQ₁Q₂ ÷ r² with k = 1 ÷ 4πε₀ ≈ 8.99 × 10⁹ N m² C⁻². The force is proportional to the product of the charges and inversely proportional to the square of their separation r. Like charges repel and unlike charges attract. Two charges of 2.0 µC, 0.30 m apart, push each other apart with a force of about 0.40 N.

The Coulomb's law formula

F = \frac{1}{4\pi\varepsilon_0}\frac{Q_1Q_2}{r^2}Force between two point charges in a vacuum
SymbolMeaningUnit
FForce between the chargesN
Q₁, Q₂The two chargesC
rDistance between the charges (centre to centre)m
ε₀Permittivity of free space, 8.85 × 10⁻¹²F m⁻¹

AQA's A-level data booklet gives Coulomb's law in this form, with ε₀ = 8.85 × 10⁻¹² F m⁻¹. Working out 1 ÷ (4π × 8.85 × 10⁻¹²) gives the Coulomb constant, k ≈ 8.99 × 10⁹ N m² C⁻², so the law is often written:

F = \frac{kQ_1Q_2}{r^2}

AQA's specification adds that air can be treated as a vacuum when calculating the force between charges, and that for a charged sphere the charge can be treated as if it were at the centre.

Attraction and repulsion

Put the signs of the charges into the formula:

  • Two positive or two negative charges give a positive F: the charges repel.
  • One positive and one negative give a negative F: the charges attract.

The force acts along the line joining the charges, and each charge feels a force of the same size, in opposite directions, as Newton's third law requires.

The inverse square law

Because r is squared on the bottom, the force falls off quickly with distance:

SeparationForce
rF
2rF ÷ 4
3rF ÷ 9
r ÷ 24F

Doubling both charges, on the other hand, multiplies the force by 2 × 2 = 4. This inverse square pattern is the same as Newton's law of gravitation, F = Gm₁m₂ ÷ r².

Coulomb's law worked examples

Example 1: two equal charges

Two charges of +2.0 µC are 0.30 m apart. Find the force between them.

Convert: 2.0 µC = 2.0 × 10⁻⁶ C.

F = \frac{8.99 \times 10^9 \times (2.0 \times 10^{-6})^2}{0.30^2} = 0.40\ \text{N}

Both charges are positive, so the force is repulsive.

Example 2: finding the separation

Charges of 3.0 µC and 5.0 µC repel with a force of 0.090 N. How far apart are they?

r = \sqrt{\frac{kQ_1Q_2}{F}} = \sqrt{\frac{8.99 \times 10^9 \times 3.0 \times 10^{-6} \times 5.0 \times 10^{-6}}{0.090}} = 1.22\ \text{m}

Example 3: charged spheres

Two small charged spheres carry +40 nC and −60 nC. Their centres are 10 cm apart. Find the force.

Treat each sphere's charge as if it were at its centre, so r = 0.10 m.

F = \frac{8.99 \times 10^9 \times 40 \times 10^{-9} \times 60 \times 10^{-9}}{0.10^2} = 2.2 \times 10^{-3}\ \text{N}

The charges are opposite, so the force is attractive.

Example 4: a proton and an electron

In a simple model of a hydrogen atom, a proton and an electron are 5.3 × 10⁻¹¹ m apart. Each has a charge of magnitude e = 1.60 × 10⁻¹⁹ C. Find the electrostatic force.

F = \frac{8.99 \times 10^9 \times (1.60 \times 10^{-19})^2}{(5.3 \times 10^{-11})^2} = 8.2 \times 10^{-8}\ \text{N}

Electrostatic force vs gravitational force

AQA's specification asks students to compare the sizes of gravitational and electrostatic forces between subatomic particles. Using the proton and electron from Example 4, with G = 6.67 × 10⁻¹¹ N m² kg⁻², a proton mass of 1.67 × 10⁻²⁷ kg and an electron mass of 9.11 × 10⁻³¹ kg from AQA's data booklet:

F_g = \frac{6.67 \times 10^{-11} \times 1.67 \times 10^{-27} \times 9.11 \times 10^{-31}}{(5.3 \times 10^{-11})^2} = 3.6 \times 10^{-47}\ \text{N}

The electrostatic force is about 2 × 10³⁹ times bigger. Both follow an inverse square law, so the ratio is the same at any separation. That is why gravity can be ignored inside atoms, and why the electrostatic force holds atoms together.

Coulomb's lawNewton's law of gravitation
EquationF = kQ₁Q₂ ÷ r²F = Gm₁m₂ ÷ r²
Depends onChargeMass
DirectionAttract or repelAlways attract
Distance dependence1 ÷ r²1 ÷ r²

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From Coulomb's law to electric field strength

Electric field strength is the force per unit charge, E = F ÷ Q. Dividing Coulomb's law by the charge feeling the force gives the field around a single point charge Q, r metres away, which AQA's data booklet lists for a radial field:

E = \frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}

For example, 0.10 m from a 2.0 µC charge, E = 8.99 × 10⁹ × 2.0 × 10⁻⁶ ÷ 0.10² = 1.8 × 10⁶ N C⁻¹. Any charge q placed there would feel a force of qE.

Common mistakes

  • Forgetting to square r. The distance is squared; the charges are not.
  • Prefixes. µC is × 10⁻⁶, nC is × 10⁻⁹ and pC is × 10⁻¹².
  • Using the surface of a sphere. Measure r between the centres of charged spheres.
  • Using diameter instead of separation. r is the distance between the two charges.
  • Reading the sign wrongly. A negative F means attraction, not a smaller force.

Coulomb's law questions with answers

1. Find the force between two 1.0 µC charges 1.0 m apart.
F = 8.99 × 10⁹ × (1.0 × 10⁻⁶)² ÷ 1.0² = 9.0 × 10⁻³ N
2. Two 5.0 nC charges are 5.0 cm apart. Find the force.
F = 8.99 × 10⁹ × (5.0 × 10⁻⁹)² ÷ 0.050² = 9.0 × 10⁻⁵ N
3. The force between two charges is 0.36 N. What is it if the separation doubles?
Inverse square: 0.36 ÷ 4 = 0.090 N
4. What is the force if instead the separation is divided by 3?
0.36 × 9 = 3.2 N (3.24 N)
5. Why can gravity be ignored when working out forces between charged particles in an atom?
The electrostatic force is about 10³⁹ times bigger than the gravitational force between them.

Practise fields in a short timed paper

A-level Physics: Year 2 gives you a short timed paper every day, with 8 questions worth 25 to 35 marks across the course, so electric fields turn up regularly but not in every paper. In AQA's A-level, electric fields are taught in the second year.

Paper resets in

Common questions

What is Coulomb's law?
The force between two point charges is proportional to the product of the charges and falls with the square of the distance between them: F = Q₁Q₂ ÷ (4πε₀r²).
What is the Coulomb constant?
k = 1 ÷ 4πε₀ ≈ 8.99 × 10⁹ N m² C⁻².
What is ε₀?
The permittivity of free space, 8.85 × 10⁻¹² F m⁻¹, given in AQA's A-level data booklet.
Do like charges attract or repel?
Like charges repel; unlike charges attract.
Is Coulomb's law an inverse square law?
Yes. Doubling the distance makes the force four times smaller.
How is Coulomb's law like Newton's law of gravitation?
Both are inverse square laws of the same form. But Coulomb's law depends on charge and can repel, while gravity depends on mass and always attracts.

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