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MathematicsAlgebra

Quadratic graphs

Quadratic graphs are the graphs of equations like y = x² − 2x − 3, where the highest power of x is 2. They are always a smooth U-shaped curve called a parabola. If the x² term is positive the curve is a U with a minimum point. If it is negative the curve is upside down, an ∩ shape with a maximum point. The key features are the roots, the y-intercept, the turning point and the line of symmetry.

What a quadratic graph looks like

Every quadratic can be written as y = ax² + bx + c, with a not zero. Drag the sliders to change a, b and c and watch the curve move. Make a negative and the parabola flips. Change b and the turning point slides sideways. Change c and the whole curve moves up or down.

y = { x}^{2}-2 x-3
-4-3-2-1123456-5510152025rootturning pointroot
Drag to pan, scroll to zoom. x from -4 to 6, y from -9 to 26.

Here x and y are the usual coordinates. It starts on y = x² − 2x − 3, the curve used in the examples below.

The features of a quadratic graph

FeatureWhat it isFor y = x² − 2x − 3
RootsWhere the curve meets the x-axis, so y = 0x = −1 and x = 3
y-interceptWhere it crosses the y-axis: the value of c(0, −3)
Turning pointThe minimum or maximum point (vertex)(1, −4)
Line of symmetryThe vertical line through the turning pointx = 1

The line of symmetry is always halfway between the two roots. Here, halfway between −1 and 3 is 1. AQA's GCSE Maths specification asks students to identify and interpret roots, intercepts and turning points graphically, including this symmetry.

How to plot a quadratic graph

To plot y = x² − 2x − 3 for x from −2 to 4, make a table of values first. Work out each y carefully: with negative x, squaring gives a positive number, so (−2)² = 4.

x−2−101234
x²41014916
−2x420−2−4−6−8
−3−3−3−3−3−3−3−3
y50−3−4−305
  1. Plot each (x, y) pair as a small cross: (−2, 5), (−1, 0), (0, −3) and so on.
  2. Join the points with a smooth curve, not straight lines. The bottom should be rounded, not pointed.
  3. Check the symmetry: the y values should mirror each other either side of the turning point. Here 5, 0, −3 on one side match −3, 0, 5 on the other.
y = x² − 2x − 3
-3-2-112345-551015(−1, 0)(0, −3)(1, −4)(3, 0)
Drag to pan, scroll to zoom. x from -3 to 5, y from -7.2 to 15.2.

How to sketch a quadratic graph

A sketch doesn't need a table: it shows the shape and the key points, labelled. Work through four steps.

Step 1: which way does it open?

Look at the sign of a, the number in front of x². Positive gives a U with a minimum. Negative gives an ∩ with a maximum.

Step 2: find the y-intercept

Put x = 0. Everything vanishes except c, so the y-intercept is (0, c).

Step 3: find the roots

Set y = 0 and solve. Factorise if you can: x² − 2x − 3 factorises to (x + 1)(x − 3). One bracket must be zero, giving roots of −1 and 3. If it won't factorise, use the quadratic formula:

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The part under the square root, b² − 4ac, is the discriminant. Positive means two roots, so the curve crosses the x-axis twice. Zero means one repeated root: the curve just touches the axis. Negative means no real roots: the curve never meets the x-axis. Try one with the formula, then press Mark to check in the course.

Use the quadratic formula to find both roots.

Press Mark to have your answer marked in the Algebra course.

Step 4: find the turning point

The turning point is on the line of symmetry, x = −b ÷ 2a. For y = x² − 2x − 3, x = 2 ÷ 2 = 1, and putting x = 1 into the equation gives y = −4. At GCSE Higher, you can also find it by completing the square:

x^2 - 2x - 3 = (x - 1)^2 - 4

In the form (x − p)² + q, the turning point is (p, q), so here it is (1, −4). Watch the sign: (x − 1)² gives p = 1, positive. Now plot the four features, draw a smooth U through them, and label each one.

A negative quadratic graph

Sketch y = −x² + 4x + 5. Here a = −1, so it is an ∩ shape. The y-intercept is (0, 5). Factorise for the roots: −x² + 4x + 5 = −(x − 5)(x + 1), so x = 5 or x = −1. The line of symmetry is halfway between, x = 2, and at x = 2, y = −4 + 8 + 5 = 9. The maximum point is (2, 9).

y = −x² + 4x + 5
-3-2-11234567-20-15-10-5510(−1, 0)(0, 5)max (2, 9)(5, 0)
Drag to pan, scroll to zoom. x from -3 to 7, y from -21 to 14.

Solving equations with a quadratic graph

A graph gives approximate solutions to equations, which AQA's specification includes alongside solving by factorising, completing the square and the formula.

  • Equal to 0: the answers are the roots, the x-intercepts, here −1 and 3.
  • x² − 2x − 3 = 2: draw the horizontal line y = 2 and read where it crosses the curve. The solutions are about x = −1.4 and x = 3.4. (The exact answers are 1 ± √6, which are −1.45 and 3.45 to 2 decimal places.)
  • x² − 2x − 3 = −5: the line y = −5 is below the turning point at −4, so it never meets the curve. There are no real solutions.

The quadratic graph calculator plots any quadratic and marks its roots, turning point and intercepts, so you can check a sketch or a reading.

Common mistakes

  • Squaring negatives wrongly. (−2)² = 4, not −4. On a calculator, use brackets.
  • Joining points with a ruler. Quadratic graphs are smooth curves with a rounded bottom.
  • Getting the turning point sign wrong. (x + 3)² − 1 has its turning point at (−3, −1).
  • Unlabelled sketches. A sketch should show the intercepts and turning point with their coordinates.
  • Misreading the scale. Check what one small square is worth on each axis before reading solutions.

To practise graphs among other topics in a short timed paper, try today's GCSE Maths Higher or GCSE Maths Foundation paper. The Graphing Functions course builds up from straight lines to parabolas, with an explorer for every part of the curve.

Common questions

What shape is a quadratic graph?
A parabola: a U shape if the x² term is positive, or an ∩ shape if it is negative.
How do you find the roots of a quadratic graph?
Read where the curve crosses the x-axis, or solve ax² + bx + c = 0 by factorising, completing the square or the quadratic formula.
How do you find the turning point?
The x-coordinate is −b ÷ 2a, halfway between the roots. Put it into the equation for y. Or complete the square: (x − p)² + q has turning point (p, q).
What is the line of symmetry of a quadratic graph?
The vertical line through the turning point, x = −b ÷ 2a. It is halfway between the two roots.
Can a quadratic graph have no roots?
Yes. If the discriminant b² − 4ac is negative, the curve never crosses the x-axis.
How do you solve an equation using a quadratic graph?
For ax² + bx + c = k, draw the line y = k and read the x-coordinates where it crosses the curve.

Revision cards

Say the answer first, then flip the card to check it.

Where to go next

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