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ChemistryMoles and quantities

Volume equations in chemistry

There are two main volume equations in GCSE Chemistry. For a gas at room temperature and pressure, volume (dm³) = moles × 24, because one mole of any gas takes up 24 dm³. For a solution, volume (dm³) = moles ÷ concentration (mol/dm³). So 0.25 mol of carbon dioxide gas fills 0.25 × 24 = 6.0 dm³, and 0.020 mol of acid at 0.50 mol/dm³ needs 0.020 ÷ 0.50 = 0.040 dm³, which is 40 cm³. At A-level, the ideal gas equation, pV = nRT, gives a gas's volume at any temperature and pressure.

Volume of a gas: V = n × 24

V = n \times 24Volume of gas in dm³ at room temperature and pressure = moles × 24

AQA's GCSE Chemistry specification states that the volume of one mole of any gas at room temperature and pressure (20 °C and 1 atmosphere pressure) is 24 dm³. This is the molar volume. It does not matter which gas: equal amounts in moles of gases take up the same volume under the same conditions of temperature and pressure.

To findUse
Volume (dm³)V = n × 24
Molesn = V ÷ 24
Volume in cm³V = n × 24 000

Remember 1 dm³ = 1000 cm³. If the volume is in cm³, divide by 24 000 to get moles.

Volume of a solution: V = n ÷ c

V = \frac{n}{c}Volume of solution in dm³ = moles ÷ concentration in mol/dm³

This comes from the concentration equation, concentration = moles ÷ volume. AQA's specification asks students to explain how the concentration of a solution in mol/dm³ is related to the mass of solute and the volume of the solution. The same rearrangement gives the volume needed in a titration.

To findUse
Concentration (mol/dm³)c = n ÷ V
Molesn = c × V
Volume (dm³)V = n ÷ c

Volumes from burettes and pipettes are in cm³, so divide by 1000 to get dm³ before using these equations.

Volume equation worked examples

Example 1: moles to gas volume

What volume does 0.25 mol of carbon dioxide occupy at room temperature and pressure?

V = 0.25 \times 24 = 6.0\ \text{dm}^3

Example 2: mass to gas volume

What volume does 8.8 g of carbon dioxide (Mr = 44) occupy at room temperature and pressure?

First the moles: 8.8 ÷ 44 = 0.20 mol. Then:

V = 0.20 \times 24 = 4.8\ \text{dm}^3

Example 3: gas volume to moles

A reaction gives off 1800 cm³ of oxygen at room temperature and pressure. How many moles is that?

n = \frac{1800}{24\ 000} = 0.075\ \text{mol}

Example 4: gas volumes from an equation

Nitrogen and hydrogen react to make ammonia: N₂(g) + 3H₂(g) → 2NH₃(g). What volume of hydrogen reacts with 30 cm³ of nitrogen, and what volume of ammonia forms?

Because equal moles of gases have equal volumes, the volumes are in the same ratio as the moles in the equation, 1 : 3 : 2. So 30 cm³ of nitrogen reacts with 3 × 30 = 90 cm³ of hydrogen to make 2 × 30 = 60 cm³ of ammonia, all measured at the same temperature and pressure.

Example 5: volume of a solution

What volume of 0.50 mol/dm³ hydrochloric acid contains 0.020 mol of HCl?

V = \frac{n}{c} = \frac{0.020}{0.50} = 0.040\ \text{dm}^3 = 40\ \text{cm}^3

Example 6: a titration volume

25.0 cm³ of 0.100 mol/dm³ sodium hydroxide is neutralised by hydrochloric acid of concentration 0.125 mol/dm³. NaOH + HCl → NaCl + H₂O. What volume of acid is needed?

Moles of NaOH = 0.100 × 25.0 ÷ 1000 = 0.00250 mol. The ratio is 1 : 1, so 0.00250 mol of HCl is needed.

V = \frac{0.00250}{0.125} = 0.0200\ \text{dm}^3 = 20.0\ \text{cm}^3

The Molarity Calculator links concentration, moles, mass and volume, and the Stoichiometry Calculator works out reacting amounts from a balanced equation.

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What volume does 0.15 mol of any gas occupy at room temperature and pressure?

The ideal gas equation: volume at any conditions (A-level)

The 24 dm³ figure only works at room temperature and pressure. At A-level, the ideal gas equation gives the volume at any temperature and pressure:

pV = nRT \quad \Rightarrow \quad V = \frac{nRT}{p}

AQA's A-level specification uses pV = nRT with the variables in SI units: p in pascals, V in m³, n in moles, T in kelvin, and the gas constant R = 8.31 J K⁻¹ mol⁻¹, which is given, not recalled.

Example 7: volume from pV = nRT

Find the volume of 0.50 mol of gas at 300 K and 100 kPa.

V = \frac{0.50 \times 8.31 \times 300}{100\ 000} = 0.0125\ \text{m}^3

That is 12.5 dm³: multiply m³ by 1000 to get dm³.

Common mistakes

  • Mixing cm³ and dm³. Divide cm³ by 1000 to get dm³. Use 24 000 for gas volumes in cm³.
  • Using 24 dm³ at other conditions. It only applies at room temperature and pressure.
  • Using the molar volume for a solid or liquid. 24 dm³ per mole is for gases only.
  • Forgetting the ratio from the balanced equation in reacting volume questions.
  • Wrong units in pV = nRT. Pressure in Pa (not kPa), volume in m³ (not dm³), temperature in K (not °C).

Volume equation questions with answers

1. Find the volume of 0.15 mol of nitrogen at room temperature and pressure.
V = 0.15 × 24 = 3.6 dm³
2. What volume does 4.4 g of carbon dioxide (Mr = 44) occupy at room temperature and pressure?
n = 4.4 ÷ 44 = 0.10 mol, so V = 0.10 × 24 = 2.4 dm³
3. How many moles are in 600 cm³ of gas at room temperature and pressure?
n = 600 ÷ 24 000 = 0.025 mol
4. What volume of 0.20 mol/dm³ solution contains 0.010 mol of solute?
V = 0.010 ÷ 0.20 = 0.050 dm³ = 50 cm³
5. In 2CO(g) + O₂(g) → 2CO₂(g), what volume of oxygen reacts with 40 cm³ of carbon monoxide?
The ratio CO : O₂ is 2 : 1, so 20 cm³.

Practise chemistry in a short timed paper

GCSE Chemistry Higher and A-level Chemistry: Year 1 each give you a short timed paper every day, with 8 questions worth 25 to 35 marks across the course, so moles, volumes and concentrations turn up regularly but not in every paper. Our guide to what a mole is covers the amount of substance these equations rely on.

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Common questions

What is the equation for the volume of a gas?
At room temperature and pressure, volume (dm³) = moles × 24. At other conditions, use pV = nRT.
What is the molar volume of a gas?
24 dm³ per mole at room temperature and pressure, 20 °C and 1 atmosphere, according to AQA's GCSE specification. It is the same for every gas.
How do you find the volume of a solution?
Volume (dm³) = moles ÷ concentration (mol/dm³). Multiply by 1000 for cm³.
Why do all gases have the same molar volume?
Gas particles are very far apart compared with their own size, so the volume depends on the number of particles, not what they are.
How do you convert cm³ to dm³?
Divide by 1000. 250 cm³ is 0.250 dm³.
What is the volume equation in physics?
In physics, volume is usually found from density: volume = mass ÷ density. The chemistry equations here are for amounts of substance in moles.

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