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ChemistryAtoms and the periodic table

Ionisation energy

Ionisation energy (ionization energy in the US) is the energy needed to remove electrons from atoms. The first ionisation energy is the energy it takes to turn one mole of gaseous atoms into one mole of gaseous 1+ ions, by taking a single electron from every atom. It generally increases across a period and decreases down a group, and the pattern of values is evidence for how electrons are arranged in shells and sub-shells.

First ionisation energy definition and equation

AQA's A-level specification asks you to define first ionisation energy and write equations for first and successive ionisation energies. Always show gaseous atoms and ions with state symbols:

Na(g) → Na⁺(g) + e⁻ first ionisation energy of sodium

The value is positive, because energy has to be put in to pull an electron away from the attraction of the nucleus. It is measured in kJ mol⁻¹.

What affects ionisation energy?

Three factors decide how strongly the outer electron is held:

  • Nuclear charge: more protons attract the electron more strongly, raising the ionisation energy.
  • Distance from the nucleus: an electron in a shell further out is held less strongly.
  • Shielding: inner electrons repel the outer electron and reduce the attraction it feels from the nucleus.

Ionisation energy across period 3

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First ionisation energy (kJ mol⁻¹, up the side) across period 3. Values are approximate, read from OpenStax Chemistry.

Across period 3, the first ionisation energy generally rises. The nuclear charge increases by one each time, but the electrons being removed are in the same shell, with similar shielding, so they are held more strongly. AQA asks you to explain how first ionisation energies in period 3 (sodium to argon) give evidence for electron configuration in sub-shells. There are two dips:

The dip from magnesium to aluminium

Magnesium's outer electron is in the 3s sub-shell (1s² 2s² 2p⁶ 3s²); aluminium's is in 3p (… 3s² 3p¹). A 3p electron has slightly higher energy and is a little further from the nucleus, and it is partly shielded by the 3s electrons, so it is easier to remove even though aluminium has one more proton. OpenStax describes this as a small deviation from the trend each time a new sub-shell begins.

The dip from phosphorus to sulfur

Phosphorus has three 3p electrons, one in each 3p orbital. Sulfur has four, so two of them share an orbital. The paired electrons repel each other, which makes one of them easier to remove, so sulfur's first ionisation energy is lower than phosphorus's.

The same pattern appears in period 2, with dips at boron and oxygen.

Ionisation energy down group 2

Approximate first ionisation energies from OpenStax:

ElementOuter sub-shellFirst ionisation energy (kJ mol⁻¹)
Be2sabout 900
Mg3sabout 730
Ca4sabout 590
Sr5sabout 550
Ba6sabout 500

Going down the group, each new element adds a shell, so the electron being removed sits further out with more inner shells screening it. The extra protons don't make up for that, so the ionisation energy falls. This is part of why the group 2 metals become more reactive down the group: their outer electrons are lost more easily.

Successive ionisation energies

The second ionisation energy removes an electron from a 1+ ion, the third from a 2+ ion, and so on:

Ca⁺(g) → Ca²⁺(g) + e⁻ second ionisation energy of calcium

Each successive ionisation energy is larger than the one before, because the electron is being removed from an increasingly positive ion. But the increase isn't smooth. A big jump appears when the next electron has to come from a shell closer to the nucleus. OpenStax explains that this jump corresponds to the removal of core electrons, which are harder to remove than the valence electrons.

Example: identifying the group

Calcium's first three ionisation energies, from OpenStax, are 589.8, 1145.4 and 4912.4 kJ mol⁻¹. The second is about double the first, but the third is over four times the second (4912.4 ÷ 1145.4 = 4.3). The big jump comes after two electrons, so calcium has two outer electrons and is in group 2.

For potassium the jump comes straight after the first: 418.8 then 3051.8 kJ mol⁻¹, a factor of about 7.3, so potassium has one outer electron, in group 1.

practice
Pick an answer, then check it.
An element's successive ionisation energies rise steadily for the first three electrons, then jump sharply for the fourth. Which group is it in?

Common mistakes

  • Leaving out state symbols. The atoms and ions must be gaseous: Mg(g) → Mg⁺(g) + e⁻.
  • Writing the second ionisation as removing two electrons. It removes one electron from the 1+ ion: Mg⁺(g) → Mg²⁺(g) + e⁻.
  • Explaining the Mg to Al dip with pairing. That dip is about the new 3p sub-shell; pairing explains the P to S dip.
  • Saying shielding increases across a period. Across a period the electrons go into the same shell, so shielding stays roughly the same while nuclear charge rises.
  • Forgetting "one mole" in the definition.

Electron arrangements are built up in the Atomic Structure course, and the electron configuration guide covers sub-shells in detail. For practice in a short timed paper, try today's A-level Chemistry: Year 1 paper.

Common questions

What is first ionisation energy?
The energy required to convert one mole of gaseous atoms into one mole of gaseous ions with a 1+ charge, losing one electron per atom.
Why does ionisation energy increase across a period?
Nuclear charge increases while the outer electrons stay in the same shell with similar shielding, so they are held more strongly.
Why does ionisation energy decrease down a group?
Each element down the group has an extra shell, so its outermost electron is more distant and better screened, and is held less strongly despite the larger nuclear charge.
Why is aluminium's first ionisation energy lower than magnesium's?
Aluminium's outer electron is in the 3p sub-shell, which is higher in energy than magnesium's 3s, so it is easier to remove.
Why is sulfur's first ionisation energy lower than phosphorus's?
In sulfur, two 3p electrons share an orbital and repel each other, so one is easier to remove.
What do successive ionisation energies tell you?
Big jumps show when electrons start being removed from a new, inner shell, so the number of electrons before the first big jump is the number of outer electrons.

Revision cards

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Where to go next

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