Maths Extension 2 (NSW) and Specialist Maths (VCE): the courses, the exams and practice questions
Maths Extension 2 & Specialist Maths
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The daily Maths Extension 2 and Specialist Maths paper has 8 original questions worth 25 to 35 marks. Its complex numbers and Argand diagram, proof by induction and polynomial roots questions fit both courses, and its volumes of revolution questions fit Specialist. Skip its hyperbolic functions, matrices, Maclaurin series, polar coordinates and second order differential equation questions: they are not topics in either course.
Maths Extension 2 in the HSC
NESA's Mathematics Extension 2 Syllabus (2024) has five Year 12 focus areas: the nature of proof, further work with vectors, introduction to complex numbers, further integration and applications of calculus to mechanics. Year 12 began it in Term 4 2026, and it is first examined in the 2027 HSC.
| Part | Marks | What's in it |
|---|---|---|
| Section I | 10 | Objective-response (multiple-choice) questions |
| Section II | 90 | 37 to 42 items, some with parts; at least two worth 4 or 5 marks |
| Whole paper | 100 | 3 hours plus 10 minutes reading time; reference sheet; NESA-approved calculators |
That is NESA's exam specification. Extension 2 results are reported in bands E1 to E4, with E4 the highest. The 2027 HSC written exams run from Wednesday 13 October to Friday 5 November 2027, and the timetable comes out on Friday 30 April 2027.
Specialist Maths in the VCE
Specialist Mathematics Units 3 and 4 (study design from 2023) have six areas of study: discrete mathematics (logic and proof, including induction), functions, relations and graphs (rational functions), algebra, number and structure (complex numbers, including De Moivre's theorem and roots), calculus (integration by parts and partial fractions, volumes and arc length, differential equations, kinematics), space and measurement (vectors, lines and planes) and data analysis, probability and statistics (confidence intervals and hypothesis tests for a mean). It assumes you are taking or have taken Mathematical Methods Units 3 and 4.
| Exam 1 | Exam 2 | |
|---|---|---|
| Time | 15 minutes reading, 1 hour writing | 15 minutes reading, 2 hours writing |
| Marks | 40 | 80: 20 multiple choice, 60 extended |
| Allowed | No technology or notes | CAS and one bound reference |
| Study score | 20% | 40% |
School-assessed Coursework is 20% in each of Units 3 and 4, and both exams come with a formula sheet. That is the VCAA's exam specification. In 2026, Exam 1 is on Monday 9 November and Exam 2 on Wednesday 11 November. For kinematics in more depth, see our Specialist maths mechanics guide.
Practice questions with answers
We wrote these for this page. Questions 1 to 4 suit both courses; question 5 is Specialist content.
1. Polar form and De Moivre's theorem. Write z = 1 + √3i in polar form and find z⁶. Answer: |z| = √(1 + 3) = 2 and arg z = tan−1(√3) = π/3, so z = 2 cis(π/3). By De Moivre's theorem, z⁶ = 2⁶ cis(6 × π/3) = 64 cis(2π) = 64.
2. Roots of a complex number. Solve z³ = −8 and show the roots on an Argand diagram. Answer: −8 = 8 cis(π), so the roots have modulus ∛8 = 2 and arguments (π + 2kπ) ÷ 3 for k = 0, 1, 2: z = 2 cis(π/3), 2 cis(π) and 2 cis(5π/3), that is 1 + √3i, −2 and 1 − √3i. They sit on a circle of radius 2, a third of a turn apart, at the corners of an equilateral triangle. The two non-real roots are conjugates, as they must be for a polynomial with real coefficients.
Check complex arithmetic with the Complex Numbers Calculator.
3. Proof by induction. Prove that 1 + 2 + 4 + … + 2n − 1 = 2n − 1 for every positive integer n. Answer: the base case n = 1 holds, since 20 = 1 = 21 − 1. Assume the result for n = k, so the first k powers of 2 sum to 2k − 1. Adding the next power, 2k, gives 2 × 2k − 1 = 2k + 1 − 1, which is the result for n = k + 1. The base case holds and each case implies the next, so by induction the statement holds for every positive integer n.
4. Integration by parts. Evaluate the integral of x ex from 0 to 1. Answer: let u = x and dv = ex dx, so the antiderivative is x ex − ex. Then (e − e) − (0 − 1) = 1. Check it with the Integral Calculator.
5. Volume of revolution (Specialist). The region under y = √x from x = 0 to x = 4 is rotated about the x-axis. Find the volume of the solid. Answer: V = π ∫ y² dx = π ∫ x dx from 0 to 4 = π × 16 ÷ 2 = 8π cubic units, about 25.1.
Use the daily paper as a trial
- Open today's paper and work to the suggested time, about 35 to 45 minutes.
- Skip the hyperbolic, matrix, Maclaurin, polar coordinate and second order differential equation questions.
- Specialist students: do the complex number and induction questions without technology, as Exam 1 practice.
- Mark it, then use NESA or VCAA past papers for vectors, integration and mechanics at full length, checking older papers against the current syllabus.
Common mistakes
- Taking the wrong quadrant for the argument. Plot the number first; tan−1 alone can't tell 1 + i from −1 − i.
- Finding only one root of zn = w. There are always n, spaced 2π ÷ n apart.
- Skipping the conclusion in an induction proof. State the base case, the assumption, the step and the final statement.
- Choosing u badly in integration by parts: let u be the factor that gets simpler when differentiated.
- Forgetting to square y in a volume of revolution: V = π ∫ y² dx.
Common questions
What is in HSC Maths Extension 2?
How long is the Maths Extension 2 exam?
Is Specialist Maths the same as Extension 2?
When is the new Extension 2 syllabus first examined?
Are these real exam questions?
Revision cards
Test yourself, then flip each card to check.
Where to go next
- Solve it
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Maths Extension 2 & Specialist Maths
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